單片機(jī)部分習(xí)題-答案

2/2單片機(jī)部分習(xí)題答案第一章思考題及習(xí)題1-11請(qǐng)寫出下列各十進(jìn)制數(shù)在八位微型機(jī)中的原碼、反碼和補(bǔ)碼形式：（1）X＝十48（2）X＝＋123（3）X＝－34（4）X＝－115真值X原碼反碼補(bǔ)碼+4830H30H30H+1237BH7BH7BH-3410100010B=0A2H0DDH0DEH-11511110011B=0F3H8CH8DH1-12將下列數(shù)看作八位微型機(jī)中帶符號(hào)數(shù)的原碼、反碼和補(bǔ)碼時(shí)，寫出相應(yīng)的真值：（1）10110110B（2）01000101B（3）11110010B（4）10101101B原碼10110110B01000101B11110010B10101101B真值X-36H=-54+45H=+69-72H=-114-2DH=-45反碼10110110B01000101B11110010B10101101B真值X-49H=-73+45H=+69-0DH=-13-52H=-82補(bǔ)碼10110110B01000101B11110010B10101101B真值X-4AH=-74+45H=+69-0EH=-14-53H=-831-13寫出下列各數(shù)的BCD碼：（1）4747H01000111B（2）78--78H01111000B（3）1996--1996H0001100110010110B（4）115--115H000100010101B1-14用十六進(jìn)制形式寫出下列字符的ASCll碼：字符串無(wú)校驗(yàn)ASCll碼奇校驗(yàn)ASCll碼偶校驗(yàn)ASCll碼（1）ESC1BH9BH1BH（2）STUDENT53H54H55H44H45H0D3H54H0D5H0C4H53H0D4H55H44H4EH54H45H0CEH54H0C5H4EH0D4H（3）X1AB9658H31H41H42H39H58H31H0C1H0C2H0D8H0B1H41H42H36H0B9H0B6H39H36H（4）COMPUTER43H4FH4DH50H55H43H4FH0CDH0D0H0C3H0CFH4DH50H54H45H52H0D5H54H45H52H55H0D4H0C5H0D2H1-15將下列數(shù)據(jù)進(jìn)行加法和減法運(yùn)算，寫在前面的數(shù)為被加數(shù)或被減數(shù)（寫出豎式）。（1）97H和OFH（2）0A6H和33H（3）0F3H和0F4H（4）0B6H和0EDH一、加法（1）97H和OFH被加數(shù)10010111B=97H加數(shù)00001111B=0FH+和10100110B=A6HC8=0,C7=00V=0,CY=0分析：無(wú)符號(hào)數(shù)：CY=0,97H+0FH=0A6H=166∵151+15=1661帶符號(hào)數(shù)：OV=0,97H+0FH=0A6H真值=-5AH=-90∵-69H+15=-105+15=-90（2）0A6H和33H被加數(shù)10100110B=A6H加數(shù)00110011B=33H+和11011001B=F9HC8=0,C7=00V=0,CY=0分析：無(wú)符號(hào)數(shù)：CY=0,A6H+33H=0D9H=217∵166+51=217帶符號(hào)數(shù)：OV=0,A6H+33H=0D9H真值=-27H=-39∵-5AH+51=-90+51=-39（3）0F3H和0F4H被加數(shù)11110011B=F3H加數(shù)11110100B=F4H+和111100111B=E7HC8=1,C7=10V=0,CY=1分析：無(wú)符號(hào)數(shù)：CY=1,F3H+F4H=100H+0E7H=1E7H=487∵243+244=487帶符號(hào)數(shù)：OV=0,F3H+F4H=0E7H真值=-19H=-25∵-13+(-12)=-25（4）0B6H和0EDH被加數(shù)10110110B=B6H加數(shù)11101101B=EDH+和110100011B=A3HC8=1,C7=10V=0,CY=0分析：無(wú)符號(hào)數(shù)：CY=0,B6H+EDH=100H+0A3H=1A3H∵182+237=419帶符號(hào)數(shù)：OV=0,B6H+EDH=0A3H真值=-5DH=-93∵-4AH-13H=-74-19=-93二、減法：（1）97H和OFH被減數(shù)10010111B－減數(shù)00001111B11110000B取反求補(bǔ)＋1加1＋11110001B進(jìn)位111110111差10001000B分析：無(wú)：CY=/C8=/1=0,∵97H-0FH=88H,151-15=1362帶：C8=1,C7=1OV=0,∵97H-0FH=88H,真值=-78H=-120∴-105-15=-120（2）0A6H和33H被減數(shù)10100110B－減數(shù)00110011B11001100B取反求補(bǔ)＋1加1